Hi. No, it's a patched version. It won't crash under circumstances like that [1] and won't succeed with invalid input:


>>> import urlparse
>>> urlparse.urlparse("http://www.google.com:foo")
ParseResult(scheme='http', netloc='www.google.com:foo', path='', params='', query='', fragment='')
>>> urlparse.urlparse("http://www.google.com:foo").port
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urlparse.py", line 105, in port
    port = int(netloc.split(':')[1], 10)
ValueError: invalid literal for int() with base 10: 'foo'
>>>