std::bit_width
From cppreference.com
| Defined in header <bit>
|
||
template< class T > constexpr int bit_width( T x ) noexcept; |
(since C++20) | |
If x is not zero, calculates the number of bits needed to store the value x, that is, 1 + floor(log2(x)). If x is zero, returns zero.
This overload participates in overload resolution only if T is an unsigned integer type (that is, unsigned char, unsigned short, unsigned int, unsigned long, unsigned long long, or an extended unsigned integer type).
Parameters
| x | - | unsigned integer value |
Return value
Zero if x is zero; otherwise, one plus the base-2 logarithm of x, with any fractional part discarded.
Notes
This function is equivalent to return std::numeric_limits<T>::digits - std::countl_zero(x);.
| Feature-test macro | Value | Std | Feature |
|---|---|---|---|
__cpp_lib_int_pow2 |
202002L |
(C++20) | Integral power-of-2 operations |
Example
Run this code
#include <bit>
#include <bitset>
#include <iostream>
int main()
{
for (unsigned x{}; x != 010; ++x)
std::cout << "bit_width( "
<< std::bitset<4>{x} << " ) = "
<< std::bit_width(x) << '\n';
}
Output:
bit_width( 0000 ) = 0
bit_width( 0001 ) = 1
bit_width( 0010 ) = 2
bit_width( 0011 ) = 2
bit_width( 0100 ) = 3
bit_width( 0101 ) = 3
bit_width( 0110 ) = 3
bit_width( 0111 ) = 3
Defect reports
The following behavior-changing defect reports were applied retroactively to previously published C++ standards.
| DR | Applied to | Behavior as published | Correct behavior |
|---|---|---|---|
| LWG 3656 | C++20 | the return type of bit_width is the same as the type of its function argument
|
made it int
|
See also
(C++20) |
counts the number of consecutive 0 bits, starting from the most significant bit (function template) |